• In this article we will see how to upload multiple files to database. 
• The main trick is to select multiple files and post it to the controller's action method.
• The saving code will be same, but will iterate for each file.

• FileId - This is primary key identity column.
• ContentType - This column stores the file type.
• ImageBytes - This column is of type varbinary and stores file bytes.

       using System;
        using System.Collections.Generic;
        using System.Linq;
        using System.Web;

        namespace FileUpload.ViewModel
        {
            public class FileUploadViewModel
            {
                public IEnumerable<HttpPostedFileBase> File { get; set; }
            }
        }
    

    @model FileUpload.ViewModel.FileUploadViewModel

@{
    ViewBag.Title = "FileUpload";
}

<h2>FileUpload</h2>



    <div>
        @using (Html.BeginForm("UploadMultipleFiles", "FileUpload", FormMethod.Post, new { @enctype = "multipart/form-data" }))
        {
            @Html.TextBoxFor(c => c.File, new { type = "file", multiple = "true" })
            <input type="submit" style="margin-left:40px;cursor:pointer;" id="upload" value="Upload"/>
        }
    </div>

       [HttpPost]
        public ActionResult UploadMultipleFiles(FileUploadViewModel fileModel)
        {
            FileUploadService service = new FileUploadService();
            foreach (var item in fileModel.File)
            {
                service.SaveFileDetails(item);
            }
            return View("FileUpload");
        }
    

       public class FileUploadService
    {
        public void SaveFileDetails(HttpPostedFileBase file)
        {
            UploadedFiles newFile = new UploadedFiles();
            newFile.ContentType = file.ContentType;
            newFile.ImageBytes = ConvertToBytes(file);
            using (FileUploadEntities dataContext = new FileUploadEntities())
            {
                dataContext.UploadedFiles.AddObject(newFile);
                dataContext.SaveChanges();
            }
        }

        public byte[] ConvertToBytes(HttpPostedFileBase file)
        {
            byte[] imageBytes = null;
            BinaryReader reader = new BinaryReader(file.InputStream);
            imageBytes = reader.ReadBytes((int)file.ContentLength);
            return imageBytes;
        }
    }
    

• We need to set the multiple attribute to true of the file control.
• The view model's property should of type IEnumerable.
• Iterate on the posted files and save it to the database.